An urn contains two red and four white balls. balls are drawn from the urn successively, at random and with replacement. what is the probability that exactly three whites occur in the first five trials?

To answer for the probability, let's consider first the given.

Given: 4 white balls, 2 red balls

Required: Probability of three (3) whites will be drawn out of five (5) trials

Solution:

Balls are drawn at random and with replacement.

Probability = (4/6)*(4/6)*(4/6) =29.6%

ANSWER: The probability of white, white, white is 29.6%

Really long apparently