Suppose that 16-ounce bags of chocolate chip cookies are produced with weights that follow a normal distribution with mean weight 16.1 ounces and standard deviation 0.1 ounce. for the distribution, approximately what percent of the bags will likely be underweight (that is, less than 16 ounces)?

To solve this we use the z statistic. The formula for z score is:

z = (x – u) / s

where x is the sample value = less than 16, u is the sample mean = 16.1, s is standard dev = 0.1

z = (16 – 16.1) / 0.1

z = - 1

From the standard distribution tables at z = - 1,

P (z = -1) = 0.1587

So about 15.87% is underweight.

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph

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step-by-step explanation: