Roscoe rides his bike at least 10 miles but not more than 30 miles. he rides at an average rate of 10.5 miles per hour. the amount of time it takes for roscoe to ride his bike  m  miles is represented by a function.   t(m)= m 10.5 what is the practical domain of the function? all integers from 0 to 50, inclusive all integers from 10 to 50, inclusive all real numbers all multiples of 20 between 0 and 1000, inclusive explain how you got your answer too, you!

Actually, the domain is the possible set of input values of a function that will make the function fit the specific criteria. In this case, the input value is m, where m is the number of miles that is travelled. The criteria is to travel at least 10 miles but not more than 30 miles, therefore the domain should be:

All real numbers from 10 to 30, inclusive

(should be real numbers not integer since any fractional number is included in the domain)

I cannot figure out why the choices are far from the answer.

the ratio of white tiles to blue tiles is 48: 16. the ratio in it's simplest form is 3: 1.

step-by-step explanation:

ratio: take the first number and add a colon next to it, then add the second number after that. make sure the ratio order matches up with the written problem!

simplest form: we can simplify the ratio 48 : 16 by dividing both terms by the greatest common factor (gcf).

the gcf of 48 and 16 is 16.

divide both terms by 16:

48 ÷ 16 = 3

16 ÷ 16 = 1

reducing to simplest form:

48 : 16 = 3 : 1

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)