The 100-meter race times at a state track meet are normally distributed with a mean of 14.62 seconds and a standard deviation of 2.13 seconds. using the standard normal probabilities table, what is the approximate probability that a runner chosen at random will have a 100-meter time less than 15.5 seconds? a.0.1894 b. 0.3409 c. 0.6591 d. 0.7910 e. 0.8106

To solve this problem, we use the t statistic. The formula for z score is:

z = (x – u) / s

where x is the sample value = 15.5 seconds or below, u is the sample mean = 14.62 seconds, s is standard dev = 2.13 seconds

z = (15.5 – 14.62) / 2.13

z = 0.41

Using standard distribution tables at z = 0.41, the value of P is:

P = 0.6591 = 65.91%

Hence there is a 65.91% chance the runner will have less than 15.5 seconds of time

c. 0.6591

step-by-step explanation:

circumference divided by 3.141592654 then timesthe radius twice

answer 1 : option "c"

answer 2 : option "d"

answer 3 : option "b"

answer 4 : option "d"

answer 5 : option "b"

answer 6 : option "a"

answer 7 : option "c"

answer 8 : option "d"

answer 9 : option "c"

answer 10 : option "d"

answer 11 : option "c"

answer 12 option "b"

answer 13 option "c"

answer 14 option "c"

answer 15 option "d"

answer 16 option "a"

answer 17 option "b"

answer 18 option "c"

answer 19 option "a"

answer 20 option "a"

answer 21 option "c"

d