Simon wanted to find the equation of a line that passes through (–6, 5) and is perpendicular to the graph of 3x + 2y = –11. his work is shown below. 1. 3x + 2y = –11 written in slope-intercept form is y = x , so the slope is . 2. the slope of the perpendicular line is . 3. substitute the point and the new slope into point-slope form to get y – 5 = (x – (– 4. simplifying, the line is y – 5 = (x + 6)

What are the values of m∠abc, m∠cbf, m∠abd and m∠dbe in the given figure? explain or show your work?

Eight people were asked what the balance of their savings account at the beginning of the month was and how much it increased or decreased by the end of the month. create a scatter plot that represents the data that is shown in the table. the x-axis represents the beginning balance in thousands of dollars and the y-axis represents the change in the savings account in hundreds of dollars. name beginning balance (in thousands of dollars) change in savings account (in hundreds of dollars) jimmy 5 3 kendra 4 7 carlos 5 4 yolanda 3 1 shawn 2 5 laura 3 2 andy 5 6 georgia 4 3

Simplify. (-2)^-3 a. -8 b. -1/8 c. 1/8 d. 8