Quadrilateral abcd is the result of a reflection of quadrilateral efgh over the line. which line segment in the image corresponds to eh in the pre-image? a.) ad b.) ab c.) bc d.) cd

A) AD

Step-by-step explanation:

Given: Quadrilateral ABCD is the result of a reflection of quadrilateral EFGH over the line.

We know that after reflection each point on the pre-image has a corresponding point on its image that is equidistant from a given line of reflection.

Since, EH shows the first and the last character of the name .

Thus, the line segment in the image corresponds to EH in the pre-image is AD because A is the first and D is the last character of the pre-image.

  21.3

step-by-step explanation:

multiplying the given equation by c/sin(25°), we get

  c = 9/sin(25°) ≈ 21.2958 ≈ 21.3

we assume "c" is the length of ab, the side opposite angle c in triangle abc.