5. the dimensions, in inches, of a shipping box at we ship 4 you can be expressed as width x, length x + 5, and height 3x - 1. the volume is about 7.6 f3. find the dimensions of the box in inches. round to the nearest inch. (hint: 1 f 1,728 in.3)

The volume of a cuboid is given by length × width × height

We have:

Volume = 7.6 ft³
Height = 3x - 1
Length = x + 5
Width = x

Substituting these into the formula, we have:

7.6 = (3x - 1) (x + 5) (x)
7.6 = [3x² + 15x - x - 5] (x)
7.6 = [3x² + 14x - 5](x)
7.6 = 3x³ + 14x² - 5x
0 = 3x³ + 14x² - 5x - 7.6

Drawing the graph is one way of finding the solution (refer to the graph below):

We have three solutions (where the curve crosses the x-axis):
x = -4.9
x = -0.6
x = 0.8

Putting these solutions back into the context, since we are looking for the value of x which is part of measurement of length, we cannot have negative value, so we will take the value of x = 0.8 ft

Converting  0.8 ft into inches = 0.8 × 12 inches = 9.6 inches

x = 9.6 inches

5/ 1/3=15 i think sorry if im wrong