How do ypu slove dis? y^2(q-4) - c(q - 4)

 3.1      Pull out     q-4 

After pulling out, we are left with : 
      (q-4) • ( y2  *  1 +( c  *  (-1) ))

 3.2      Factoring:  y2-c 

Theory : A difference of two perfect squares,  A2 - B2  can be factored into  (A+B) • (A-B)

Proof :  (A+B) • (A-B) =
         A2 - AB + BA - B2 =
         A2 - AB + AB - B2 = 
         A2 - B2

Note :  AB = BA is the commutative property of multiplication. 

Note :  - AB + AB equals zero and is therefore eliminated from the expression.

Check :  y2  is the square of  y1 

Check :  c1   is not a square !! 
Ruling : Binomial can not be factored as the difference of two perfect squares

graph them on a graphing calculator, press 2nd trace. select intersect. hit enter until it says answer. ti 84 works best

step-by-step explanation:

first, you divide the triangle in two, tô form a retangle triangle. after, using pythagoream theorem:

18^2 = 14^2 + (x/2)^2

(x^2/4) + 196 = 324

x^2/4 = 324 - 196

x^2/4 = 128

x^2 = 512

x = √512

x = √2^9

x = 16√2 cm

i hope i you.