At the annual dogs show chantel noticed that there were three more scottie’s than schnauzers. she also realized that the number of wire haired terriers was five less than twice the number of schnauzers if there were 78 dogs in all how many schnauzers were their?

Let us start with the schnauzers, the easiest one to imagine. Let us assume that there were x number of schnauzers. Scottie's are 3 more than schnauzers. So their number is x+3 Wire haired terriers are 5 less than twice the number of schnauzers. So their number is 2x -5 (2x for twice the number of schnauzers) Now add all these numbers. That is x + x+3 + 2x-5 = 4x -2 The total number of dogs, 78, is given in the question Now we know that 4x -2 =78 4x = 78 +2 = 80 Therefore x = 80/4 = 20. So there were 20 schnauzers, 23 Scottie’s and 35 wire haired terriers

Im sorry but what on