Part 1. create two radical equations: one that has an extraneous solution, and one that does not have an extraneous solution. use the equation below as a model. a√x+b+c=d use a constant in place of each variable a, b, c, and d. you can use positive and negative constants in your equation. part 2. show your work in solving the equation. include the work to check your solution and show that your solution is extraneous. part 3. explain why the first equation has an extraneous solution and the second does not.

1)a) b)2) Solving and Checking on section 1 3) Commonly when we square both sides and there's an x on the right side outside the radical equation, an extraneous solution arises.

Step-by-step explanation:

1 &2) An extraneous solution does not satisfy an equation. So let's evaluate:

Checking for extraneous solution:

1 and 2) Another radical equation:

Checking:

4 satisfies the equation.

3) Because when we change the radical equation into quadratic one, and both sides are squared, very often the second solution does not satisfy the equation. That happened when we squared x.

6,250

step-by-step explanation:

to get the area, multiply 360 by 160.(57,600)

to find out how many bags of fertilizer it will take, first figure out how many square feet one bag can hold. divide 1000 by 8(125) to get the unit rate(how many square feet one pound of fertilizer can hold)and multiply it by 50(6250). if i haven't made a mistake, that is the answer.

step-by-step explanation:

we have

using a graphing tool

see the attached figure

this is a quadratic equation (vertical parabola) open up

the vertex is a > vertex

the domain of the function is all real > interval (-∞,∞)

the range of the function is the > [-6.125,∞)

the function has two x->   and

the function is increasing over the > (0.25,∞)

the function is decreasing over the > (-∞,0.25)