The longest side of an acute isosceles triangle is 12 centimeters. rounded to the nearest tenth, what is the smallest possible length of one of the two congruent sides? a) 6.0 cm b) 6.1 cm c) 8.4 cm d) 8.5 cm

Option D

Step-by-step explanation:

we know that

In an acute triangle

where

c is the longest side of triangle

a,b the other two sides of triangle

In this problem we have an acute isosceles triangle

so

substitute

------> rewrite

----->Round to the nearest tenth

D)8.5 cm

Step-by-step explanation:

We are given that an acute isosceles triangle  in which longest side is 12 cm.

Isosceles triangle is that triangle in which two sides of triangle are equal.

Let x be the length of congruent sides

We know that when  a triangle is an acute triangle then it satisfied the given inequality equation

a=b by definition of isosceles triangle

Substitute the values then we get

Divide by 2 on both sides then we get

Taking square root in both sides

a=8.5 cm

Hence, the smallest possible length of one of two congruent sides=8.5 cm

41*67/2=1373.5

step-by-step explanation:

i just used a calculator