The first aircraft has 73 more seats than the second aircraft. the third aircraft has 57 fewer seats than the second aircraft. if their total number of seats is 427 find the number of seats for each aircraft.

First aircraft seats : x
second aircraft seats : y
third aircraft seats : z

The first aircraft has 73 more seats than the second aircraft: x = y + 73

The third aircraft has 57 fewer seats than the second aircraft: z = y - 57

Their total number of seats is 427: x + y + z = 427

solve these three equations, you will get:

x = 210 seats
y = 137 seats
z = 80 seats


 you can check your answer by:

x - y = 210 - 137 = 73  correct

and

z + 57 = 80 + 57 = 137 = y correct