F(x)=t-2(x+4)^2 where t is the constant. if f(-8.3)=f(a) and a > 0 what is the value of a ?

We are given the equation:

F (x) = T – 2 (x + 4)^2                      ---> equation 1

 

Since we know that f (-8.3) = f(a) and a>0, therefore from equation 1 we can generate that:

(x + 4)^2 = (a + 4)^2

(-8.3 + 4)^2 = (a + 4)^2

(-4.3)^2 = (a + 4)^2

(a + 4)^2 = 18.49

a + 4 = 4.3

a = 0.3

0=6x+2y+10 is equivalent to the simplified form: y= -3x - 5• parallel lines always have the same slope, different y intercept knowing this, we can say the slope, or m of the line parallel to y= -3x - 5 is -3.m= -3 hope this could !

The answer is: y would equal 3 because if you simplify the equation then it would be y= 3x+9 and if you divide 3x and 9 by 3 it would equal 3. y= 3