Acompany is creating a box without a top from a piece of cardboard, but cutting out square corners with side length x. which expression can be used to determine the greatest possible volume of the cardboard box? (x−10)(x−30)x (10−2x)(30−2x)x (10−x)(30−x)x (30x−10)(10x−30)

Choice B) The expression (10-2x)(30-2x)x represents the volume of the box




The original width is 10 inches. The width reduces to 10-2x inches after we cut off the top two corners of the rectangle. We can think of it as taking 10 and subtracting off two copies of x like so: 10-x-x = 10-2x

Similarly, the length goes from 30 inches to 30-2x inches. This time we're taking off the top and bottom corners (focus on either side it doesn't matter). 

The height of the box is x inches due to this portion being folded up. 

Volume of box = (width)*(length)*(height)
Volume of box = (10-2x)(30-2x)x

Note: the units for the answer are in cubic inches which can be written as "in^3" (inches cubed). 

2160ft^3 i think you could use a formala to you out with this in the future