How can you use place value when using partial quotients?

The “partial quotients” strategy uses place value and lets students to form on multiplication facts with friendly numbers. Look at the problem 496 ÷ 4. There are three instances of a student’s method to answering 496 ÷ 4. We could say that example C is more effectual than the other two but it is vital to point out how the student is thinking on comprehending. The students can multiply 4 x 20 over and over again or use higher multiples of ten proficiently; they all touch the same solution. The “partial quotient” way will work with any division problem.

(see attachment below)

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step-by-step explanation:

geometry: triangles

solvers

lessons

answers archive

call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

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