The sum of three consecutive integers is 63 find the three integers

663/3 = 21

21 is the middle number,

21+1 = 22

21-1 = 20

20 + 21 + 22 = 63

Our three consecutive integers can be represented as

X → first integer

X + 1 → second integer

X + 2 → third integer

If the sum of our three consecutive integers is 63, our equation will read...

X + X + 1 + X + 2 = 63

Now, we can simplify on the left. Once we simplify, our equation will now read

3x + 3 = 63

      -3    -3  ← subtract 3 on both sides

  3x = 60 ← divide both sides by 3

   X = 20

Our three consecutive integers can be represented as

X → first integer = 20

X + 1 → second integer = 21

X + 2 → third integer = 22

Therefore, the three consecutive integers are 20, 21, and 22.

make sure you have version 2.50

try looking in the very back of the book : )

step-by-step explanation:

you can download it here

answer4 to the second power is 16

and 4 to the third power is 64,