Mathematics, 04.07.2019 01:00 aubreymoore4553
Find the slope at tangent line f(x)=(3/2)x+1 at (-2,-2)
Answers: 1
![\bf f(x)=\cfrac{3}{2}x+1\implies \cfrac{df}{dx}=\cfrac{3}{2}\qquad \stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})} \\\\\\ \stackrel{(-2,-2)}{y-(-2)=\cfrac{3}{2}[x-(-2)]}\implies y+2=\cfrac{3}{2}(x+2)\implies y+2=\cfrac{3}{2}x+3 \\\\\\ y=\cfrac{3}{2}x+1](/tpl/images/0048/3558/9365a.png)
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