Abasketball team sells tickets that cost $10, $20, or, for vip seats, $30. the team has sold 469 tickets overall. it has sold 112 more $20 tickets than $10 tickets. the total sales are $8300 how many tickets of each kind have been sold?

X + y + z = 469 (1)

x  + 112 = y   (2)

10x + 20y + 30z = 8300 (3) 

Replace (x + 112) for y to (1) and (3) equations: 

  x +     x  + 112   + z = 469 
⇒2x          +        z        = 357 

   10x + 20( x + 112 ) + 30z = 8300 
⇒ 30x + 30z = 6060 
 Simplify, divide equation by 30
⇒x + z = 202 

Put these 2 equations together:
  2x          +        z        = 357 
  x            +        z        = 202 

x                                  = 155  $10 tickets sold 

(2)  155 + 112= 267 $20 tickets sold 

z - ( 115 + 267) = 469 

z                       = 87 $30 tickets sold 

The answer would be d i think but i’m for sure it is not a and c