Afireman, 57.6 m away from a burning building, directs a stream of water from a fire hose at an angle of 35.2° above the horizontal. if the initial speed of the stream is 42.7 m/s, at what height will the stream of water strike the building?

First calculate the time it takes to reach the building using the x-component of the velocity.

t = 57.6 m / (42.7 m/s * cos35.2) = 1.65 s

Then we calculate the height y using the y-component of the velocity:

y = (42.7 m/s * sin35.2) * 1.65 s – 0.5 (9.81 m/s^2) (1.65 s)^2

y = 11.26 m

true? is that what you're asking or do you mean something else?

2 x t divided by n

step-by-step explanation: