Which method do you prefer to use to find sums__count by tens and ones, use compatible numbers, or use friendly numbers and adjust? explain why.

I count by tens and ones. Let me show you why with an example;

X=56+27

What is x?

To solve this equation, all you have to do is add 56 and 27. Easy. Since there are 7 tens, (5 plus 2), 7 will be in the tenths place. Like this: 7_. What will be next to it? To find this, just add the ones. 6+7=13. “Uh. Oh, 13 is bigger than ten,) you might be wondering. This problem has a simple fix. How many tens are in 13? One. You add ten to your 7, and you now have 8 in your tens place. Add the remaining three ones, and you’ve got your answer. 83.

56+27=83

X=83.

This method is easier and faster than any other method. Did you know calculators are actually programmed to use this method for simple addition? Who would’ve thought?

38+105= 143, 39+104=143, and you will find then adding the numbers on opposite sides, moving inwards yields the answer 138 every time. because of this, you’re going to multiply 138 times the number of pairs, which is 34. therefore, 34*138= 4692(i’m sorry if it’s the wrong numbers, but it’s the right concept)