Mathematics, 03.07.2019 17:50 YoVeoAnime

Aballoon is released on top of a building. the graph shows the height of the balloon over time. what does the slope and y-intercept reveal about the situation?

Aballoon is released on top of a building. the graph shows the height of the balloon over time. what

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Answer from: sportie59

C. The balloon starts at a height of 500 ft and rises at a rate of 150 ft.

Step-by-step explanation:

We have been given a graph which represents the height of the balloon over time.

We can see from our graph that y-intercept, which represents the height of the balloon (in thousand feet) at time equals zero, is 0.5. To find the correct y-intercept we will multiply 0.5 by 1000 as height of the balloon is given in thousand feet.

$\text{y-intercept}=(0.5\times 1000)\text{ feet}=500\text{ feet}$

Therefore, y-intercept represents that the balloon starts at a height of 500 feet.

Now let us find slope of our given line using slope formula.

$\text{Slope}=\frac{y_2-y_1}{x_2-x_1}$

y_2-y_1 is vertical change or rise.

x_2-x_1 is horizontal change or run.

Upon substituting given values in above formula we will get,

$\text{Slope}=\frac{3.5-0.5}{20-0}$

$\text{Slope}=\frac{3}{20}$

$\text{Slope}=0.15$

Now let us multiply 0.15 by 1000 as height of balloon is given in thousand feet.

$\text{Slope}=0.15\times 1000=150$

Therefore, slope of our line is 150 which means that height of balloon is increasing 150 feet per second or balloon is rising at a rate of 150 feet per second.

Upon looking at our given options we can see that option C is the correct choice.

Answer from: anna40794

The slope is (change in y)/(change in x). Taking (0, 0.5) and (10, 2) since the x axis is horizontal and the y axis vertical, we get the slope to be (2-0.5)/(10-0)=
1.5/10=3/20=0.15. Since it's based off of 1000 feet, we multiply 0.15 by 1000 to get 150 as the rate of change for every x value. In addition, since we start at 0.5, 1000*0.5=500 and we therefore start at 500 ft. Using the information we have, we therefore have C as our answer

Answer from: Quest

The answer is something i don’t know

Answer from: Quest

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v