Solve the following system of equations and show all work. y = −x^2+4 y = 2x+1

Since both equations have y on the left-hand side, set them equal:

2x+1=-x^2+4

Add x^2 and subtract 4:

x^2+2x-3=0

Factor to get:

(x+3)(x-1)=0

Thus, x=1 or -3.  Substituting in for x, y=2*1+1=3 or y=-3*2+1=-5.  Therefore, our ordered pairs are (1, 3) and (-3, -5).

Cfhxr tu ivxdriizae6iklvd

300b(x) is graphed by the functio