Two bags had 100 kilograms of sugar each. after taking out 3 times as much sugar from bag one than bag two, bag one had half as much sugar left as bag two. how much sugar is left in each bag?

According to the given statement, we can get the equation:

50 - 3x = 1/2 (50-x)

where x = amount removed from bag two, 3x removed from bag one

Then we multiply both sides by 2 (to eliminate the ½)

100-6x= 50-x

Add 6x to both sides

100= 50-5x

Then subtract 50 from both sides

50=5x

Lastly, divide by 5

10=x

Therefore 10 kg of sugar was removed from bag 2

further, 3x= 30, so 30 kg of sugar was removed from bag 1.

50-30=20 kg remaining in bag 1.

50-10=40 kg remaining in bag 2.

y = - 6

step-by-step explanation:

given the point (- 2, y) lies on the graph then it is a solution of it's equation.

substitute x = - 2 into the equation for value of y

y = 3(- 2) = 3 × - 2 = - 6

the point on the graph is (- 2, 6)

answer is d-29

step-by-step explanation:

since you didn't include the picture, i can give you the description so you know how to pick the correct answer. the third quartile of a data is always shown in a box plot. in the middle of your graph should be a box. the third quartile is the value that goes with the far right edge of the box.