What is the probability of rolling a number less than or equal to 8 with two dice, given that at least one of the dice must show a 6?

Step-by-step explanation:

Events :

{1,1} ;{1,2};{1,3};{1,4};{1,5};{1,6}

{2,1} ;{2,2};{2,3};{2,4};{2,5};{2,6}

{3,1} ;{3,2};{3,3};{3,4};{3,5};{3,6}

{4,1} ;{4,2};{4,3};{4,4};{4,5};{4,6}

{5,1} ;{5,2};{5,3};{5,4};{5,5};{5,6}

{6,1} ;{6,2};{6,3};{6,4};{6,5};{6,6}

Total events = 36

Favorable events = Sum of number less than or equal to 8 with two dice, given that at least one of the dice must show a 6 = {1,6};{2,6};{6,1} ;{6,2} =4

Probability of getting an event =

So,  probability of rolling a number less than or equal to 8 with two dice, given that at least one of the dice must show a 6 =

                                                                       =

Thus , the probability of rolling a number less than or equal to 8 with two dice, given that at least one of the dice must show a 6 is

hi there!

the answer to this question is d: 35

step-by-step explanation:

5 to the power of 2 is 25

2 multiplied by 5 is 10

then you add the 2 numbers and you get 35