The perimeter of a rectangular field is 380yd. the length is 50 yd longer than the width. find the dimensions.

P = 2(L + W)
P = 380
L = W + 50

380 = 2(W + 50 + W)
380 = 2(2W + 50)
380 = 4W + 100
380 - 100 = 4W
280 = 4W
280/4 = W
70 = W <=== width is 70 yds

L = W + 50
L = 70 + 50
L = 120 <=== length is 120 yds

The answer is 270 cars.you can do this by making a proportional relationship. for instance, 200 is the whole we are using, so on a “number line” 200 would be over 100%. now, since he sells 35% more, add 35% to 100% to get 135% on the other side of the “number line” on the bottom half, leaving the top half empty.cross multiply 200 by 135 then divide by 100 to get your answer. i hope this , if it did, , if you don’t mind, giving me brainiest! 200/100% } 200 • 135 /100 ? /135%

Xis -1/2
y is 35/4.