Avacuum cleaner costs $68, and the full-replacement extended warranty costs $22. if the manufacturer sells 360,920 vacuum cleaners under warranty and must replace 15% of them to honor the warranties, how much will the replacement costs be?

$3,681,384.

Step-by-step explanation:

A vacuum cleaner costs = $68

and replacement extended warranty costs = $22

Total sale of vacuum cleaners under warranty = 360,920

Vacuum cleaners must replace = 15%

First we calculate the number of vacuum cleaners that need to be replace

15% × 360,920

= 0.15 × 360,920

= 54,138

Since these vacuum cleaners need to be replaced free of cost to the consumers, the cost to the company will be selling price of the units.

Therefore, cost of replacement = 54,138 × 68 = $3,681,384

The cost of replacement would be $3,681,384.

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.