Mathematics, 02.07.2019 13:10 Queenhagar

The bakery bought 4 bags of flour containing 3.5 kg each. 0.475 kg of flour is needed to make a batch of muffins, and 0.65 kg is needed to make a loaf of bread. if 4 batches of muffins and 5 loaves of bread are backed, how much flour will be left? give your answer in kilograms.

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Answer from: davelopez979

The left out amount of floor is $\boxed{\bf8.85\,\,{\text{kilogram}}}$ .

Further explanation:

The weight of one bag of flour is 3.5 kg.

The bakery bought 4 bags of flour.

Therefore, the total weight of 4 bags is calculated as follows:

$4\times\left({3.5\,\,{\text{kg}}}\right)=14\,\,{\text{kg}}$

The weight of flour needed for a batch of muffins is 0.475 kg.

Therefore, the weight of flour needed for 4 batches of muffins is calculated as follows:

$4\times\left({0.475\,\,{\text{kg}}}\right)=1.9\,\,{\text{kg}}$

The weight of flour needed for a loaf of bread is 0.65 kg.

Therefore, the weight of flour needed for 5 loaves of bread is calculated as follows:

$5\times\left({0.65\,\,{\text{kg}}}\right)=3.25\,\,{\text{kg}}$

So, the total weight of floor used in the process of making muffins and loaves of bread is calculated as follows:

$3.25\,\,{\text{kg+}}1.9\,\,{\text{kg}}=5.15\,\,{\text{kg}}$

Now, the weight of floor that is left out in the bag is calculated as follows:

$14\,\,{\text{kg}}-5.15\,\,{\text{kg}}=8.85\,\,{\text{kg}}$

Thus, the left out amount of floor is $\boxed{\bf8.85\,\,{\text{kilogram}}}$ .

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Answer details:

Grade: Middle School

Subject: Mathematics

Chapter: Basic Algebra

Keywords:

Bakery, bags, flour, 3.5 kg, muffins, bread, loaf, loaves, kilograms, kg, share, subtract, equally, 8.85 kg, weight, bought

Answer from: Quest

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v