Train a leaves a station at 8: 00 and travels at 100 km per hour towards the next city. one and a half hours later, train b, an express, leaves the same station, traveling at 160 km per hour along the same route. at what time will train b overtake the slower train?

Let t be time in hours.

Train A travels at 100 km per hour, so after t hours it will be 100t km from the station.

Train B travels at 160 km per hour, but it leaves the station one and a half hours later than train A, so its time is (t-1.5) hours. After (t-1.5) hours it will be 160(t-1.5) km from the station.

Train B will overtake train A when their distances from the station are equal.


Train B will overtake train A after 4 hours since train A left the station. It left the station at 8:00, so train B will overtake it at 12:00.

This makes absolutely no sense at all young man/women

It is 5.8 you add all of the up to equat 180 then solve the equation