Abiased coin is flipped the probability of getting heads is 80% a player wins 2$ each time he gets tails and a game involves 10 tosses what is the expected value of the money earned in a game?

The expected value is $4.

Step-by-step explanation:

We have that the probability of winning is equal to 20% (or 0.20 in decimal form)

The expected value can ve calculated as:

Ev = (p₁x₁ + p₂x₂ + + pₙxₙ)

Where x stands for a given event, and p for the probability of the event.

Here we have:

x₁ = winning $2

p₁ = 0.20

x₂= not winning anithinh.

p₂ = 0.80

Then for each flip the expected value is:

Ev = 0.2*$2 + 0.8*$0 = 0.2*$2

and in 10 flips, we have 10 times that amount:

Total expected value = 10*0.2*$2 = 2*$2 = $4

overpriced

step-by-step explanation:

a_n = a_1 + (n - 1)d

the first term is 6.

the common difference d = ?

when you find d, replace n with 7 and d with the common difference to find your answer.