On number 48 can someone tell me how to do this?

So, basically you'll need to change the equation 8x-5y=3 into y=mx+b format.

If you do that, you'll get
y=8/5x - 3/5

Now, you know the slope of the equation. It's positive 8/5.

Using the equation of a line y-y1=m(x-x1), plug in the values of the coordinate 8x-5y=3 passes through.

So... you'll get:

y-(-1)=8/5(x-(-2))

y+1=8/5(x+2)

From here on, just simplify so you can get the slope intercept form.

y = 8/5x + 11/5

However, you're not done yet. The problem is looking for an equation of a line perpendicular to the one we currently have. So, we need the slope which is perpendicular to 8/5.

In order to get that, we need to use the negative reciprocal. So, basically we switch the places of the numerator and denominator and make it a negative.

The perpendicular reciprocal of 8/5 is -5/8.

Looking at the choices above, the only choice given with -5/8 as the slope is A.

So, the answer is: A y = -5/8x - 9/4