Two cars traveled equal distances in different amounts of time. car a traveled the distance in 4 h, and car b traveled the distance in 4.5 h. car b traveled 5 mph slower than car a. (the formula r⋅t=d , where r is the rate of speed, t is the time, and d is the distance can be used.) how fast did car b travel? enter your answer in the box.

Given that car B travelled 5 mph slower than car A, let the rate (R) at which car B travelled be x, then the rate at which car A travelled is given by x + 5.

Given the formular RT = D, then the distance travelled by car A is given by 4(x + 5) and the distance travelled by car B is given by 4.5x.

Given that both cars travel an equal distance, then 4(x + 5) = 4.5x
4x + 20 = 4.5x
4.5x - 4x = 20
0.5x = 20
x = 20 / 0.5 = 40

Therefore, car B travel at 40 mph.

The answer would be 7 cages