Which equation can you solve to find the potential solutions to the equation log2x + log2(x – 6) = 4?

The value of x from the given logarithmic expression are -2 and 8

Given the expression

log2x + log2(x – 6) = 4

Applying the product rule in indices

log2(x(x-6)) = 4

log2(x²-6x) = log2 16

Cancelling log on both sides, we will have;

x² - 6x = 16

Equate to zero

x² - 6x - 16 = 0

x² -8x +2 x - 16 = 0

x(x-8) + 2(x-8) = 0

x = -2 and 8

Hence the value of x from the given logarithmic expression are -2 and 8

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If the question is

which can be simplified to

By the definition of log, means

=>

2^4=x(x-6)=x^2-6x

Simplify and solve for x

x^2-6x-16=0

(x+2)(x-8)=0

x=-2 or x=8

Since no answer choices are given, one of the equations in the above solution should appear in the answer choices.

the answer is 0052

0 0 5 2

5 0 2 6 3 5

− 0

2 6

− 0

2 6 3

− 2 5 0

1 3 5

− 1 0 0

3 5