What value for x makes the following statement true?

2

Step-by-step explanation:

we can isolate the variable by subtracting 3x from both sides

3x + 12 = 5x + 8

-3x          -3x      

        12 = 2x + 8

and then subtracting 8 from both sides

12 = 2x + 8

-8           -8

4 = 2x

then we divide by 2 on both sides

 4 = 2x

÷2   ÷2

2 = x

flip the equation to get:

x=2

checking the solution by plugging in 2 in place of x:

(3 * 2) + 12 = (5 * 2) + 8

6 + 12 = 10 + 8

18 = 18

since the equation is true,

the solution x = 2 is correct.

you are saying it as if a fact, not a question, but yes, you would be correct? ; )

step-by-step explanation:

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2