Find a polynomial of the specified degree that satisfies the given conditions. degree 4; zeros -1, 1, square root 5; integer coefficients and constant term 10

the 2 figures are congruent bc if you reflect abcd over the y axis then over the d axis the figures overlap

f(x) is going down by 4

step-by-step explanation:

(its either that or its going left by 4)

explanation:

step-by-step explanation:

the polynomial is a perfect square trinomial of the form a^2-2ab+b^2:

option a. true

step-by-step explanation:

9x^2-12x+4

comparing with the form a^2-2ab+b^2

1.) a^2=9x^2

solving for a: square root both sides of the equation:

sqrt(a^2)=sqrt(9x^2)

a=sqrt(9) sqrt(x^2)

a=3x

2.) b^2=4

solving for b: square root both sides of the equation:

sqrt(b^2)=sqrt(4)

b=2

to be a perfet square trinomial 2ab must be equal to 12x. let's check:

2ab = 2 (3x) (2)

2ab = 12x

correct