Find 2 sum whose sum is 4806 and difference is 1050 explanation

The two numbers are 2928 and 1878

Step-by-step explanation:

Given this information, we can set up two equations:

x + y = 4806

x - y = 1050

We can solve these simultaneous equations by elimination, which means we can either add or subtract the two equations to solve one of the variables.

In this case, adding the equations together will eliminate y so we can solve for x (remember that y + - y is the same as y - y):

   x + y = 4806

+  x - y = 1050

   2x     = 5856

This can then be simplified to x = 2928 (by dividing by 2)

Now we know x, we can substitute this value into any equation to find y:

2928 + y = 4806 so y = 4806 - 2928 which is 1878.

The two numbers are 2928 and 1878.

Hope this helps!

(-1,-0.5)

step-by-step explanation:

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15