What is the solution to this system of equations?
6x - 2y = 8
1-3x + y = -4
A. No Solution
B. (0, -4)
C. Infinite Solutions

No solution

Step-by-step explanation:

System of Linear Equations given :

[1]           6x-2y=8

 [2]           1-3x+y=-4

Equations Simplified or Rearranged :

  [1]    6x - 2y = 8

  [2]    -3x + y = -5

Solve by Substitution :

// Solve equation [2] for the variable  y

 [2]    y = 3x - 5

// Plug this in for variable  y  in equation [1]

  [1]    6x - 2•(3x-5) = 8

  [1]    0 = -2 =>  NO solution

3/4 ÷ 3/4

step-by-step explanation:

basically divide any proper fraction with itself to fit the criteria.

so if we are using 3/4, then:

3/4 ÷ 3/4 = 1

so 1 is the quotient.

and the numerators for both these fractions is 3.   and if we divide the numerators:

3 ÷ 3 = 1

we see that quotient is equal to our original quotient as well.

answer: idk

step-by-step explanation: