I need help asap Find the perimeter of a square having two consecutive vertices at (7,2) and (3,3).

47 - 90 = 43

43 - 180 = x

x = 137

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given the equation is 8+9z=-6, the first step would be to subtract the 8 from both sides:

8+9z-8=-6-8

since 8 minus 8 = 0, this would cancel out the 8. and since -6 minus 8 equals -14, the equation would look like this

9z = -14