The price of Stock A at 9 A. M. was $12.41. Since then, the price has been increasing at the rate of $0.12 each hour. At noon the price of Stock B was $13.16. It begins to decrease at the rate of $0.14 each hour. If the two rates continue, in how many hours will the prices of the two stocks be the same?

1.50 Hours

Step-by-step explanation:

Given:

To Find:

If the two rates continue, in how many hours will the prices of the two stocks be the same?

Solve:

Price of stock A at 9 a.m.= $12.41

The price has been increasing at the rate of $0.12 each hour.

Increase in price after 3 hours = 0.12 × 3 = 0.36

Price of Stock A at noon= 12.41+0.36 =12.77

Let n be the no. of hours after which the prices of both the stocks will be same .

So, Increase in price after n hours = 0.12 n

Price of Stock A after n hours = 12.77+0.12 n

Price of stock B = 13.16

The price has been decreasing at the rate of $0.14 each hour.

Let n be the no. of hours

So, Increase in price after n hours = 0.14 n

Price of Stock B after n hours =13.16-0.14 n

ATQ

12.77 + 0.12n = 13.16 - 0.14n

-12.77 + 13.16 = 0.12n + 0.14n

0.39 = 0.26n

0.39/0.26 = n

n = 1.50

Hence the prices of the two stocks be the same after 1.50 hours after 12 pm .

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