A rectangular pool is 6 feet long and 5 feet wide. It is filled to a depth of 2 Teet. A cubic footof water is about 7.5 gallons. If the pool can be filled at a rate of about 10 gallons per minute, now long will it take to fill the pool to a depth of 2 feet? Explain your reasoning. *QUICK*

450 minutes

Step-by-step explanation:

First, let's calculate the volume of the pool when filled.  Volume will be: (length x width x height).

Volume = 6' x 5' x 2 ' = 60 ft^3

1 ft^3 of water occupies 7.5 gallons.  That's a conversion factor for water:  (7.5 gal)/(1 ft^3).

The total gallons of water in a filled pool would be:\

(60 ft^3)*((7.5 gal)/(1 ft^3)) = 4500 gallons

At a rate of 10 gallons/min, it would take:

(4500 gallons)/(10 gallons/min) = 450 minutes, or 450/60 = 7.5 hours

9

step-by-step explanation:

the answer is:

the correct option:

b.

to solve the problem, we need to remember how to operate to simplify exponential expressions using the logarithms.

we are given the equation:

then, using placing logarith with base 7 on both sides of the equation, we have:

so, rounding the obtained result to two decimal places (nearest hundreth), we have:

hence, we have that the correct option:

b.

have a nice day!