Find the 2nd, 3rd and 4th term of the geometric sequence
4.5,_,_,_,364.5

Step-by-step explanation: This is a geometric progression, so apply the formula:

, where a = first term in the sequence

r = common ratio

n = position of term

So first find r, which is the common ratio, and after that just substitute the numbers into the equation. n is the only thing that changes.

Refer to the picture for solving

(brainiest please :) )

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.