PLEASE HELP I have 3 round stock tanks. I want to use the one with the largest volume in my cow-calf pasture. (That's where my cows that are having calves are held.) I want to use the one with the smallest volume in the corrals with the horses. It is easier to fill it when necessary. I don't mind running the hose on it everyday. I want to use the tank with the mid-sized volume in my bull pasture. I have 15 bulls for sale. I have people come by everyday so the number of animals in that pasture will go down. Please match the correct tank with the correct pasture.

77

step-by-step explanation:

what level of math? also i don't need to be paid if i can you.

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240

answer is 33

step-by-step explanation: