Which confidence level would produce the widest interval when estimating the mean of a population based on the mean and standard deviation of a sample of that population? NO LINKS!!! a. 99%
b. 80%
c. 95%
d. 90%

The relation is

Higher the confidence level wider the interval.

So option A i.e 99% is correct

idk

step-by-step explanation:

use that smart brain

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116