X is partly constant, and partly varies as y. When y= 2 , x = 30 and when y = 6, x = 50 a) Find the relationship between x and y
b) Find x when y = 3

"X is partly constant and partly varies as y"

---> x = ky + p

when y=2,x=30 ---> 30 = 2k + p

when y=6,x=50 ---> 50 = 6k + p

subtract: 20 = 4k

k = 5

sub back in the first: 30 = 10+p

p = 20

x = 5y + 20

now you can answer B

notice this is just a variation of y = mx + b

"X is partly constant and partly varies as y"

---> x = ky + p

when y=2,x=30 ---> 30 = 2k + p

when y=6,x=50 ---> 50 = 6k + p

subtract: 20 = 4k

k = 5

sub back in the first: 30 = 10+p

p = 20

x = 5y + 20

now you can answer B

notice this is just a variation of y = mx + b

the answer   is 200

step-by-step explanation:

this is a problem about poisson probabilities.   i don't know if you've

already studied poisson distributions, or if you have a place to look

to read more about the subject.  

here's how you can see a poisson distribution coming.   when there are

a lot of events that may happen at any time (or any place), and when

you're counting how many of them happen at a particular time (or a

particular place), and each event is independent of the others, then

the result is a poisson distribution.   this is roughly true for the

chocolate chips; one chip being in a cookie has only a small effect on

the probability that another chip will be in the cookie.

once you know you have a poisson distribution, you know a lot.   there

is only one parameter to a poisson distribution, so if you know the

mean, you know everything.   the form of the distribution is

  probability of n chips = {[e^(-x)]*(x^n)} / (n! )

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: