estimate the perimeter of a school chalkboard, measuring 76 cm by 46 cm. Give your answer to the nearest ten

260

Step-by-step explanation:

76 rounded to 1 s.f. is 80

46 rounded to 1s.f. is 50

80+50+80+50= 260

Hope this helps!

240 cm (to the nearest ten)

Step-by-step explanation:

perimeter of a rectangle = 2W + 2L

where W is the width and L is the length

To estimate the perimeter, first round the components to the nearest ten then carry out the calculation.

Given:

⇒ estimated perimeter = 2 x 50 + 2 x 80 = 100 + 160 = 260 cm

Alternatively, to calculate the actual perimeter and then round the answer to the nearest ten:

⇒ actual perimeter = 2 x 46 + 2 x 76 = 92 + 152 = 244 cm

⇒ perimeter = 240 cm (to the nearest ten)

step-by-step explanation:

the original amount doesn't ''re just looking for the time it takes for 1/2 of the substance to we have

(1/2) =)     take the ln   of both sides

ln (1/2)   = )   and we can write

ln(1/2) = ) lne     and lne   = 1     so we have

ln(1/2) = -.1092t     divide both sides by -.1092

t = ln(1/2)/-.1092 = about 6.347 days = about 6.3 days (rounded)

4th option is correct xy=-10

if this was to u plzz mark me the brainliest