We are given with a inequality and we have to find the solution for it . So , let's start :
![{:\implies \quad \sf 6x-5\ -29}](/tpl/images/2676/1411/13c97.png)
Adding 5 to both sides :
![{:\implies \quad \sf 6x-\cancel{5}+\cancel{5}\-29+5}](/tpl/images/2676/1411/0a7b1.png)
![{:\implies \quad \sf 6x\ -24}](/tpl/images/2676/1411/a1036.png)
Dividing both sides by 6 ;
![{:\implies \quad \sf \dfrac{\cancel{6}\cdot x}{\cancel{6}}\ -\dfrac{24}{6}}](/tpl/images/2676/1411/e9dcf.png)
![{:\implies \quad \bf \therefore \quad \underline{\underline{x \ -4}}}](/tpl/images/2676/1411/19b5d.png)
Hence , Option A) x > - 4 is correct :D
Note :-
Whenever dividing or multiplying an inequality by a -ve , so we have to tilt the sign too , while if we are multiplying or dividing with a +ve , so sign will remain the same , For example like if we are given with x > y , and we multiply both sides by -1 . So , it will then become - x < - y