The vertex of a parabola is at (6,5), and its axis of symmetry is vertical. One of the x-intercepts is at (8, 0). What is the x-coordinate of the other x-intercept?

Step-by-step explanation:

Vertex form of the quadratic equation:

where the vertex is

Given vertex = (6, 5):

If one the x-intercepts is (8, 0):

Therefore, equation of parabola:

x-intercepts occur when f(x) = 0:

Therefore, the x-coordinate of the other x-intercept is 4.

x = 25

step-by-step explanation:

a^2+b^2=c^2

7^2+24^2=c^2

49+576=625

sqrt625=25

x=25

-7/8

step-by-step explanation:

instead of subtracting you add the -6/8 and -1/8