The random and 10% conditions are met. Is the Large Counts condition met? Yes, the smallest expected count is 5.85, so all expected counts are at least 5. Yes, the smallest expected count is 6, so all expected counts are at least 5. No, the smallest expected count is 0.04, so the expected counts are not all at least 5. No, the smallest expected count is 0.05, so the expected counts are not all at least

step-by-step explanation:

659

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)

e. hinduismt religion first emerged on the indian subcontent

the answer is  

a.

28 ft2

step-by-step explanation: