The graph of the function f(x) = –(x + 3)(x – 1) is shown below. On a coordinate plane, a parabola opens down. It goes through (negative 3, 0), has a vertex at (negative 1, 4), and goes through (1, 0).

Which statement about the function is true?

A) The function is positive for all real values of x where x < –1.

B) The function is negative for all real values of x where x < –3 and where x > 1.

C) The function is positive for all real values of x where x > 0.

D) The function is negative for all real values of x where x < –3 or x > –1.

The second statement is true.

Step-by-step explanation:

"The function is positive" means the graph is above the x-axis.  The  y  values are positive.

"The function is negative" means the graph is below the x-axis.  The  y  values are negative.

The first statement is false because there are values of  x  less than -1 where the graph is below the x-axis (example:  x = -4).

The second statement says the graph is below the x-axis for values of  x  in two places:  x to the left of -3,  x to the right of 1.  That's true.

The third statement is false because there are values of  x  to the right of 0 where the graph is below the x-axis.

The fourth statement is false. It is correct that the graph is below the x-axis for all x < -3, but for x > -1, the graph lies partly above and partly below the x-axis.

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

we can't see all full 4 options, but if this is the full option, than the very left one is correct:

-2/5 * -3 3/4

remake the question, adding a picture of all the question, or write down the full left and right answers.