The steps in writing f(x)=18x+3x2 in vertex form are shown, but a value is missing in the last step. Write the function in standard form. Factor a out of the first two terms. f(x)=3(x2+6x) Form a perfect square trinomial. (six-halves) squared f(x)=3(x2+6x+9)−3(9) Write the trinomial as a binomial squared. f(x)=3(x+___)2−27 What is the missing value in the last step? 3 6 9 18

missing value is 3

Step-by-step explanation:To find the vertex form of parabola  given in almost standard form  were written following steps:

1.  Write the function in standard form:

2. Factor a out of the first two terms:

3. Form a perfect square trinomial:

4. Write the trinomial as a binomial squared:

The vertex is (-3,-27).

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

my answer got deleted but it's a

step-by-step explanation: