Hw #5 trapezoids and kites practice Please help me answer any of these few questions, any help is greatly appreciated!!!

Step-by-step explanation:

First Problem:

Given: m< ABC = 70; m< ADC = 46

line AC and line BD are perpendicular bisectors based on the definition of parallelograms.

m< 4 = 90

Line BD bisects < ABC

70/2 = 35

m< 2 = 35  ;  m< 3 = 35

Line BD bisects < ADC

46/2 = 23

m< 8 = 23  ;  m< 9 = 23

All the three angles of a triangle add up to 180.

180 - (90 + 35) = 55

m< 1 = 55  ;  m< 5 = 55

180 - (90 + 23) = 67

m< 6 = 67  ;  m< 7 = 67

Third Problem:

<BCE = <ECD because line AC bisects <BCD

9x - 1 = 2x + 13

9x - 2x = 13 + 1

7x - 14

x = 2  ;  m< ECD = 2

line AC and line BD are perpendicular bisectors based on the definition of parallelograms. So, <CED = 90

All the three angles of a triangle add up to 180.

180 - (90 + 2) = 88

m< EDC = 88

3. (5x + 1) - (-10x + 6)

simplify the answer choice. combine like terms. remember to distribute the negative to the terms inside the second parenthesis. also remember that two negatives = one positive, and one of each sign = negative.

- (-10x + 6) = + 10x - 6

simplify. combine like terms:

5x + 1 + 10x - 6

5x + 10x + 1 - 6

15x - 5

∴ it is your answer

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